Author Login Editor-in-Chief Peer Review Editor Work Office Work

Computer Engineering ›› 2020, Vol. 46 ›› Issue (7): 185-191. doi: 10.19678/j.issn.1000-3428.0055353

• Mobile Internet and Communication Technology • Previous Articles     Next Articles

Spectrum and Energy Efficiency Equilibrium Scheme for Decode and Forward Relay Networks

GAO Zhongxiaa,b, QIU Runhea,b   

  1. a. College of Information Science and Technology;b. Engineering Research Center of Ministry of Education of Digitized Textile and Apparel Technology, Donghua University, Shanghai 201620, China
  • Received:2019-07-02 Revised:2019-08-23 Published:2019-09-09

解码转发中继网络频谱与能量效率的均衡方案

高仲霞a,b, 仇润鹤a,b   

  1. 东华大学a. 信息科学与技术学院;b. 数字化纺织服装技术教育部工程研究中心, 上海 201620
  • 作者简介:高仲霞(1995-),女,硕士研究生,主研方向为协作中继高能效传输;仇润鹤,教授、博士。
  • 基金资助:
    国家自然科学基金面上项目(61671143)。

Abstract: In order to reduce network resource consumption and ensure green communication,this paper proposes a scheme to balance Spectrum Efficiency(SE) and Energy Efficiency(EE) of Decode and Forward(DF) Two-Way Relay Transmission(TWRT) and One-Way Relay Transmission(OWRT).The spectrum efficiency of DF-TWRT and DF-OWRT are increased by using the optimal power allocation method,and the expressions of SE and EE of TWRT and OWRT systems are obtained under the optimal power allocation.The relationship between SE and EE is analyzed,and the energy efficiency of the two systems is maximized by optimizing the total transmission power.Simulation results show that the SE and EE of the proposed scheme are higher than those of equal power allocation at the same data transmission rate.

Key words: One-Way Relay Transmission (OWRT), Two-Way Relay Transmission (TWRT), Decode and Forward(DF), Spectrum Efficiency(SE), Energy Efficiency(EE), power

摘要: 为减少网络资源消耗以保证绿色通信,提出一种解码转发(DF)双向中继传输(TWRT)和单向中继传输(OWRT)频谱效率和能量效率均衡方案。采用最优功率分配方法提高DF-TWRT和DF-OWRT的频谱效率,得到最优功率分配下TWRT系统和OWRT系统的频谱效率和能量效率表达式,并分析频谱效率和能量效率之间的关系,通过优化发射总功率实现两种系统的能量效率最大化。仿真结果表明,与等功率分配相比,该方案在相同数据传输速率下的频谱效率和能量效率更高。

关键词: 单向中继传输, 双向中继传输, 解码转发, 频谱效率, 能量效率, 功率

CLC Number: