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Computer Engineering ›› 2021, Vol. 47 ›› Issue (2): 188-193. doi: 10.19678/j.issn.1000-3428.0056935

• Mobile Internet and Communication Technology • Previous Articles     Next Articles

Resource Allocation Algorithm for Internet of Vehicles Based on LTE-V2X

YU Xiang, CHEN Xiaodong, WANG Zheng, SHI Xueqin   

  1. School of Communication and Information Engineering, Chongqing University of Posts and Telecommunications, Chongqing 400065, China
  • Received:2019-12-17 Revised:2020-02-21 Online:2021-02-15 Published:2020-02-28

基于LTE-V2X的车联网资源分配算法

余翔, 陈晓东, 王政, 石雪琴   

  1. 重庆邮电大学 通信与信息工程学院, 重庆 400065
  • 作者简介:余翔(1964-),男,教授,主研方向为无线通信;陈晓东、王政、石雪琴,硕士研究生。
  • 基金资助:
    国家科技专项计划(2017ZX03001004-004)。

Abstract: In the LTE-V2X system of Internet of Vehicles(IoV),there are two ways of resource allocation:centralized mode and distributed mode.To address the problems faced by the Sense-based semi-Persistent Schedule(SPS) resource allocation algorithm for distributed mode,such as half-duplex errors,hidden terminal errors and resource block conflicts,this paper proposes an improved SPS algorithm based on driving direction for freeway scenarios.According to the characteristics of the driving direction on freeway,the resource pool is divided into two sub-pools to reduce the potential interference between the vehicles going in opposite directions.On this basis,each resource block is allowed to carry location information to reduce the collision probability of the SPS algorithm when resources are reselected.Experimental results show that the proposed algorithm can significantly improve the Packet Reception Ratio(PRR) compared with the existing SPS algorithm.

Key words: LTE-V2X technology, resource allocation, resource pool, resource collision, Internet of Vehicles(IoV)

摘要: 在车联网中的LTE-V2X系统中,资源分配包括集中式和分布式2种方式,针对分布式方式下SPS资源分配算法存在的半双工错误、隐藏终端错误和资源块冲突等问题,提出一种高速公路场景中基于行车方向的改进SPS算法。根据高速公路行车方向的特点,将资源池划分为2个子资源池,以减少相反方向车辆用户之间的潜在干扰。使每个资源块携带位置信息,从而降低SPS算法在资源重选时的碰撞概率。实验结果表明,与传统SPS算法相比,该算法可以有效提高分组接收率。

关键词: LTE-V2X技术, 资源分配, 资源池, 资源碰撞, 车联网

CLC Number: